7-Zip command line to extract a folder from an archive

I'm using the 7-Zip commandline to extract a ZIP archive called abc.zip which is an archive with a folder called 'zipper' with three text files in it (a.txt, b.txt, and c.txt).

My problem is when I extract it with the following command:

7z e C:\abc\abc.zip -y oC:\abc

7-Zip extracts everything, but it doesn't extract the folder 'zipper', it just extracts a.txt, b.txt and c.txt and puts them in the output destination (that is, C:\abc).

How can I make 7-Zip just extract the actual folder?

4 Answers

You need to use 7z x archive.zip to extract with full paths. See:

There should probably be a hyphen in front of the o:

-oC:\abc

Also consider the -r option for recursion.

I had to solve a similar problem. Here is the code I used. This script receives a folder and unzips all zips (and deletes them afterwards). The trick is to unzip the data into a special folder. A little bit edgy but it works...

@echo off
set SEVEN_ZIP_HOME=C:\Program Files\7-Zip
set TEMPDIR=temp
set WORKING_DIR="%1"
if "%WORKING_DIR%"=="" set WORKING_DIR=%~dp0
cd /d %WORKING_DIR%
if not exist %TEMPDIR% md %TEMPDIR%
for %%i in ("%WORKING_DIR%\*.zip") do call :unzipAndDelete "%%i"
rd %TEMPDIR%
goto :end
:unzipAndDelete
set ZIP_FILE=%~1
call :extractName %ZIP_FILE%
call "%SEVEN_ZIP_HOME%\7z.exe" e "%ZIP_FILE%" -o./%TEMPDIR%
copy .\%TEMPDIR%\*.* %FILENAME%.log
del .\%TEMPDIR%\*.* /q
del "%ZIP_FILE%"
goto :end
:extractName
set FILENAME=%~n1
goto :end
:end

Be careful with considering -rThe doc explicitly says :-)

-r[-|0]
Recurse subdirectories (CAUTION: this flag does not do what you think, avoid using it)