Compute the determinant by cofactor expansions.
A=
| 1 -2 5 2| | 0 0 3 0| | 2 -4 -3 5| | 2 0 3 5|I figured the easiest way to compute this problem would be to use a cofactor across row 2. So I got:
det A =
|-1 -2 2| -3| 2 -4 5| | 2 0 5|I went on to factor across the third row.
det A =
( |-2 2| |-1 -2|) -3(2|-4 5| + 5| 2 -4|)det A = -3(2(-10+8)+5(4+4))
det A = -3(-4+40)
det A = -108
When I check my work on a determinate calculator I see that I should be getting det A = 12, but I can't seem to see where I'm messing up.
$\endgroup$ 11 Answer
$\begingroup$The top left entry on the second matrix got copied wrong, it should be 1 not -1.
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