I have never encountered a problem like this and am a bit confused.
Function $f$ satisfies:
$f(3)=5$, $f(9)=7$
$f'(3)=11$, $f'(9)=13$
Find an equation for the tangent line to the curve $y=f(x^2)$ at point $(x,y) = (3,7)$.
I don't know where to start. I drew a graph of the points related to the slope of the derivative but that doesn't really help me, and I don't understand the concept of $y = f(x^2)$.
A point in the right direction would be great, thank you for any help!
$\endgroup$ 01 Answer
$\begingroup$Hint 1: By the Chain Rule, we have $\frac{dy}{dx}=(2x)f'(x^2)$.
Hint 2: The information about $f(3)$ and $f'(3)$ is meant to lead you astray. Not nice!
$\endgroup$ 6
