How do I find the symmetry point for a graph based on a quadratic equation?
$\endgroup$ 31 Answer
$\begingroup$For an equation of the form $y= ax^2 + bx + c $ the axis of symmetry lies on the x-value $ \frac{-b}{2a}\ $.
$\endgroup$ 0How do I find the symmetry point for a graph based on a quadratic equation?
$\endgroup$ 3For an equation of the form $y= ax^2 + bx + c $ the axis of symmetry lies on the x-value $ \frac{-b}{2a}\ $.
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