I want to plot x(t)=t*exp(-3*t)+0.25*exp(-3*t), and its first and second time derivatives.
I cannot even get the first plot correct. This is what I have done.
t = [0:0.01:3];
x = t*exp(-3*t)+0.25*exp(-3*t);
figure
plot(t,x);From what I understand, that is saying that t goes from 0 to 3 in steps of 0.01 and x is the function I defined at that t. MatLab gives me this error
"Error using * Inner matrix dimensions must agree."
Can someone please let me know what's going on? I'm a matlab noob. I use mathematica quite a bit and I have used octave for making plots of data, but never to plot functions. I always do that stuff with mathematica!
$\endgroup$ 32 Answers
$\begingroup$you have to have
x = t.*exp(-3.*t)+0.25*exp(-3.*t)this will do element by element multiplication
.* is the element by element multiplication for a vector, * is just multiplication.
Plotting and taking derivatives of functions in Matlab is perfectly easy. First you just need to use the symbolic math capabilities:
syms t;
x = t*exp(-3*t)+0.25*exp(-3*t);
xdot = diff(x,t,1)
xddot = diff(x,t,2)Then to plot these you have several options. You can substitute in numeric values using subs, which automatically vectorizes your equations so you don't need to worry about adding .*:
t_ = 0:0.01:3;
x_ = subs(x,t,t_);
xdot_ = subs(xdot,t,t_);
xddot_ = subs(xddot,t,t_);
plot(t_,x_,'b',t_,xdot_,'g',t_,xddot_,'r')Or you can use the ezplot function to directly plot the symbolic function over a range:
subplot(131);
ezplot(x,[0 3]);
subplot(132);
ezplot(xdot,[0 3]);
subplot(133);
ezplot(xddot,[0 3]);The function fplot is another option if you convert your symbolic equations to numeric functions. This can be done manually or via the matlabFunction function:
subplot(131);
fplot(matlabFunction(x),[0 3])
subplot(132);
fplot(matlabFunction(xdot),[0 3])
subplot(133);
fplot(matlabFunction(xddot),[0 3])
